# How do you graph #y=x^2+8-3x#?

##### 1 Answer

Here's one way: **complete the square** to find its vertex, then calculate a few more points by plugging in values of

#### Explanation:

Let's rearrange the equation:

This equation can't be factored, so let's complete the square:

This is the equation in **vertex form:**

We know the vertex is

The leading coefficient **opens upwards.**

We can get a few more points of the parabola by plugging in some values of

Substituting

Substituting

Substituting

Substituting

Graph and connect these points. Be sure to label the equation of the graph, label the axes, and include arrowheads.